/**
 * Converts a 4 byte array of unsigned bytes to an long
 * @param b an array of 4 unsigned bytes
 * @return a long representing the unsigned int
 */
public static final long unsignedIntToLong(byte[] b) 
{
    long l = 0;
    l |= b[0] & 0xFF;
    l <<= 8;
    l |= b[1] & 0xFF;
    l <<= 8;
    l |= b[2] & 0xFF;
    l <<= 8;
    l |= b[3] & 0xFF;
    return l;
}
    
/**
 * Converts a two byte array to an integer
 * @param b a byte array of length 2
 * @return an int representing the unsigned short
 */
public static final int unsignedShortToInt(byte[] b) 
{
    int i = 0;
    i |= b[0] & 0xFF;
    i <<= 8;
    i |= b[1] & 0xFF;
    return i;
}

You can use my BinaryTools class freely, at http://cvs.sourceforge.net/viewcvs.py/joustim/joscar/src/net/kano/joscar/BinaryTools.java?view=markup

It provides methods for dealing with binary data, including two methods very similar to the two you posted. It uses my ByteBlock class, but you could easily change it (using IDEA's structural search & replace for example) to use byte arrays.

if you want it to run at least 8 times slower you can wrap the byte array in a java.nio.ByteBuffer and use its getInt method

You could try doing it like this. It is basically the same, but much faster. For the unsignedShortToInt, it is about 1/3 faster, where unsignedIntToLong is five times faster. <pre> public static final long unsignedIntToLong(byte[] b) { return (b[0] << 24) | (b[1] << 16) | (b[2] << 8) | b[3]; }

public static final int unsignedShortToInt(byte[] b) { return (b[0] << 8) | b[1]; } </pre>

Shortest version would be (masking to 0xff is necessary):

return ((b[0] & 0xFF) << 24) | ((b[1] & 0xFF) << 16) | ((b[2] & 0xFF) << 8) | b[3] & 0xFF;

You can probably can do some bytecode tweaking to make it bit shorter but not necessary faster.

Good work dude !!! Thanks I needed it.

This code converts directly from an int to a long.

int i = ...; long l = i < 0 ? 0x0000000100000000L + i : i;

on my pc (J2SE V1.4.2_04), I have to cast to a long before each operation:

return ((long)(b[0] & 0xFF) << 24) | ((long)(b[1] & 0xFF) << 16) | ((long)(b[2] & 0xFF) << 8) | (long)b[3] & 0xFF;

Exactly what I was looking for, thanks!

Thanks guys, just what I was looking for!

A probably slower but more flexible way is:

int i = new BigInteger(1,bytes).intValue();

which takes any length array. Especially handy for doing IP filtering for both IPv4 and IPv6

Very useful, thank you

thanx...

i wasnt '&' it with FF. my code worked because i never tested with values which would give me a -ve int. but looking at this i realized that it had a bug and it sometimes might not work without the '& 0xFF'

Just another alternative for converting directly from an int (treated as unsigned) to a long:

int i = ...; long res = (i & 0x7FFFFFFF) + ((long)(i>>>31)<<31);

Hope someone (other than me!) finds that helpful

// Just an observation ... // The value of uiLong1 after the bit // shifts will be the C++ unsigned int // equivalent of -9999 long uiLong1 = -9999; uiLong1 <<= 32; uiLong1 >>>= 32;

i'm getting 145 in first byte, tht means 8th bit will be on, when it reaches after shifting on 32th bit, if cozez the signed bit to on, which changes the value...wht'll be the solutiion...thnx in adv

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And how about value & 0xffffffffL????

As for casting an unsigned short to an int, this is even easier i you have the short to start with: (int)(char)ushort Why does this work? char is the only unsigned numeric primitive in Java.

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Good luck !

There is a difference in little endian and big endian byte order. I had to exchange b[0] and b[1] to get little endian with unsignedShortToInt.

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There's a much easier way to do it:

to byte array - BigInteger.valueOf(num).toByteArray()

from byte array - new BigInteger(array).intValue()

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Since java version 1.4, use of ByteBuffer makes these conversions easier, keeping the details of the conversion obfuscated. Unfortunately, when reading binary data files one must either know or be able to detect byte ordering, i.e. little/bin endian, for proper conversion.

For example;

import java.nio.ByteBuffer;

public class tt { static public void main(String[] args) throws Exception { byte[] buffer = new byte[55];

// Initialize a network byte order int to 1234 buffer[2] = (byte)0x04; buffer[3] = (byte)0xD2;

// Use ByteBuffer.getInt() to "convert" the byte[] to int int ival = ByteBuffer.wrap(buffer).getInt();

// Print out the value System.out.println("length is " + ival); } // public static void main(String[] args) } // public class tt

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You can use java.nio.ByteBuffer of you want to convert an array of bytes into a stream of integers.

ByteBuffer keyBuffer = ByteBuffer.wrap(rowByteArray);

try { int nextInt = keyBuffer.getInt(); // do operations on the integer here } catch(BufferUnderflowException e) { // handle the last 3 bytes }